What is the product of your drop height, age, height, and weight?

[onelesscar]

wow, only 550,620.

why is it that the most pointless threads get the most responses the fastest?

[forrestunifreak]

Originally Posted by Spencer Hochberg

Yours is 873,600...product means multiply

I am 554,400.

Ohhhh, are we supposed to be serious?

[JJtheunicycle]

Originally Posted by forrestunifreak

Ohhhh, are we supposed to be serious?

stupid montana people......uh oh

[ntappin]

6.5x18x70x125 for a whopping 1023750

On Thu, 31 Aug 2006 08:55:55 -0500, wobbling bear wrote:

>mine is 2217.456 ... metric (meters, age, meters, kilograms)

Mine is 89,970,284,195 in proper SI units, and counting. That's the
highest number posted so far, yay!

Klaas Bil - Newsgroup Addict
--
"I'm slowly but surely stealing Wales and bringing it back to my house on the wheel, frame and cranks of my muni. - phil"

[harper]

Originally Posted by Klaas Bil

Mine is 89,970,284,195 in proper SI units, and counting. That's the
highest number posted so far, yay!

Oooohhh. Seconds. Should have thought of that.

[Klaas Bil]

Originally Posted by harper

Oooohhh. Seconds. Should have thought of that.

On second thought, yeah.

[AscenXion]

Originally Posted by harper

What is the product of your drop height, age, height, and weight?

Drop height in feet. Age in years. Height in inches. Weight in pounds.

Mine is 3,744,900 foot-year-inch-pounds.

Beat that, sissies.

I think you're onto something. However, I belive it should be something more like:

Age / [ (Rider Height / Drop Height) X (Rider Weight / Unicycle Weight) X Time Unicyling ]

Use all of the same units for each of the same measurements and this not only gives you a straight ratio with no units, but it also gives you a much more accurate representation of...something.

You're way I'm 1,037,400 ftyrinlb

My way I'm 3.74

Just seems much tidier.

[AscenXion]

Originally Posted by maestro8

Let's give this one a try.

8.89 cm * sz 12 * 5.5 in * 1.5 yds = 880.11 cm-sz-in-yds

Hmm... not quite as large a number. I must be doing something wrong.

It's okay that it's only 5.5 inches...the girls are always saying that it's not size, but prowess.

ntappin
6.5x18x70x125 for a whopping 1023750

you're 5'10" and only 125 lbs...I think you have more to worry about.

[harper]

Originally Posted by AscenXion

I think you're onto something. However, I belive it should be something more like:

Age / [ (Rider Height / Drop Height) X (Rider Weight / Unicycle Weight) X Time Unicyling ]

Use all of the same units for each of the same measurements and this not only gives you a straight ratio with no units, but it also gives you a much more accurate representation of...something.

You're way I'm 1,037,400 ftyrinlb

My way I'm 3.74

Just seems much tidier.

Good. Someone is taking this far too seriously. I feel my work here is done.

[koebwil]

Am I seriously going to be the first one to say 768?

[Monocyclist]

3.454 googols. I win.

[tomblackwood]

Originally Posted by MuniAddict

Just figured mine; it's: I DON'T CARE! Besides, I'm bad at math!

But you sure are good at clicking the Reply button.

Back to the original question posed by this thread, I only get 1,165,500 foot-year-inch-pounds. You are right Harper, I am a sissy. A young, stumpy, svelte sissy.

Right now, I think the only factors I can influence that will make much of a difference are drop height and weight. By mid-winter, I should have a better multiplier on the weight side. On drop height, does it need to be one I've landed, or can I count the higher ones where I've chickened out and bailed?

[steveyo]

851,400

[harper]

Originally Posted by tomblackwood

On drop height, does it need to be one I've landed, or can I count the higher ones where I've chickened out and bailed?

Who's monitoring any of these parameters? Who does for any of these silly threads. Klaas' answer was best because he realized seconds (in true, uniform SI units) would yield a much higher number. People who respond to these silly threads just want to see big numbers. Who's to say that you're not a seven foot tall, 350 pound behemoth? Why can't you be 60 years old? Did anyone need to see you land that twenty foot drop? And better, go Klaas' direction and use the cgs system. Fransisco and Childs are the ones who really saw through it.